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path: root/tests/conformance/3-expressions/prec_left_andand.zc
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// expect: 1/1/1/1/0/0/1/1/0/0/0/0/0/0/0/0/0/0/1/1/1/1/1/1/1/1/1/1/1/1/1/1/0/0/
// first operator && followed by each other binary operator; operands chosen so that the two groupings differ
include rt;
void pn(int x) { rt.put_n(x); rt.put_c(10); }
fn main() {
	pn(0 && 6 || 8);
	{ int a = 0, b = 6, c = 8; pn(a && b || c); }
	pn(5 && 4 | 4);
	{ int a = 5, b = 4, c = 4; pn(a && b | c); }
	pn(3 && 7 ^ 7);
	{ int a = 3, b = 7, c = 7; pn(a && b ^ c); }
	pn(-2 && 12 & 6);
	{ int a = -2, b = 12, c = 6; pn(a && b & c); }
	pn(-2 && 6 == 1);
	{ int a = -2, b = 6, c = 1; pn(a && b == c); }
	pn(0 && 8 != 8);
	{ int a = 0, b = 8, c = 8; pn(a && b != c); }
	pn(7 && 9 < 5);
	{ int a = 7, b = 9, c = 5; pn(a && b < c); }
	pn(3 && -3 > -2);
	{ int a = 3, b = -3, c = -2; pn(a && b > c); }
	pn(1 && 12 <= 4);
	{ int a = 1, b = 12, c = 4; pn(a && b <= c); }
	pn(7 && 4 >= 2);
	{ int a = 7, b = 4, c = 2; pn(a && b >= c); }
	pn(-2 && 2 << 4);
	{ int a = -2, b = 2, c = 4; pn(a && b << c); }
	pn(-3 && 9 >> 3);
	{ int a = -3, b = 9, c = 3; pn(a && b >> c); }
	pn(5 && -3 + 4);
	{ int a = 5, b = -3, c = 4; pn(a && b + c); }
	pn(8 && -1 - 6);
	{ int a = 8, b = -1, c = 6; pn(a && b - c); }
	pn(-2 && 3 * 7);
	{ int a = -2, b = 3, c = 7; pn(a && b * c); }
	pn(-2 && 3 / -1);
	{ int a = -2, b = 3, c = -1; pn(a && b / c); }
	pn(9 && 100 % 5);
	{ int a = 9, b = 100, c = 5; pn(a && b % c); }
	return 0;
}