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path: root/tests/conformance/3-expressions/prec_left_ge.zc
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// expect: 1/1/0/0/5/5/-3/-3/0/0/0/0/1/1/0/0/0/0/0/0/0/0/1/1/1/1/0/0/0/0/0/0/1/1/1/1/
// first operator >= followed by each other binary operator; operands chosen so that the two groupings differ
include rt;
void pn(int x) { rt.put_n(x); rt.put_c(10); }
fn main() {
	pn(-8 >= 8 || 7);
	{ int a = -8, b = 8, c = 7; pn(a >= b || c); }
	pn(5 >= 12 && 2);
	{ int a = 5, b = 12, c = 2; pn(a >= b && c); }
	pn(6 >= 7 | 5);
	{ int a = 6, b = 7, c = 5; pn(a >= b | c); }
	pn(-1 >= 5 ^ -3);
	{ int a = -1, b = 5, c = -3; pn(a >= b ^ c); }
	pn(9 >= 12 & 8);
	{ int a = 9, b = 12, c = 8; pn(a >= b & c); }
	pn(1 >= 12 == 12);
	{ int a = 1, b = 12, c = 12; pn(a >= b == c); }
	pn(-3 >= -2 != 5);
	{ int a = -3, b = -2, c = 5; pn(a >= b != c); }
	pn(0 >= 1 < 0);
	{ int a = 0, b = 1, c = 0; pn(a >= b < c); }
	pn(5 >= 100 > 5);
	{ int a = 5, b = 100, c = 5; pn(a >= b > c); }
	pn(12 >= 12 <= -1);
	{ int a = 12, b = 12, c = -1; pn(a >= b <= c); }
	pn(1 >= 9 >= 7);
	{ int a = 1, b = 9, c = 7; pn(a >= b >= c); }
	pn(6 >= -1 << 7);
	{ int a = 6, b = -1, c = 7; pn(a >= b << c); }
	pn(6 >= 100 >> 5);
	{ int a = 6, b = 100, c = 5; pn(a >= b >> c); }
	pn(4 >= 1 + 8);
	{ int a = 4, b = 1, c = 8; pn(a >= b + c); }
	pn(-1 >= 9 - -8);
	{ int a = -1, b = 9, c = -8; pn(a >= b - c); }
	pn(7 >= 4 * 5);
	{ int a = 7, b = 4, c = 5; pn(a >= b * c); }
	pn(2 >= 8 / 0);
	{ int a = 2, b = 8, c = 0; pn(a >= b / c); }
	pn(7 >= 9 % 5);
	{ int a = 7, b = 9, c = 5; pn(a >= b % c); }
	return 0;
}