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// expect: 1/1/1/1/-7/-7/1/1/-4/-4/0/0/1/1/1/1/0/0/1/1/0/0/0/0/-2/-2/-2/-2/-9/-9/4/4/0/0/1/1/
// first operator % followed by each other binary operator; operands chosen so that the two groupings differ
include rt;
void pn(int x) { rt.put_n(x); rt.put_c(10); }
fn main() {
pn(2 % 5 || 2);
{ int a = 2, b = 5, c = 2; pn(a % b || c); }
pn(-1 % 100 && 100);
{ int a = -1, b = 100, c = 100; pn(a % b && c); }
pn(7 % 6 | -8);
{ int a = 7, b = 6, c = -8; pn(a % b | c); }
pn(3 % 100 ^ 2);
{ int a = 3, b = 100, c = 2; pn(a % b ^ c); }
pn(-2 % -8 & -3);
{ int a = -2, b = -8, c = -3; pn(a % b & c); }
pn(9 % 6 == 2);
{ int a = 9, b = 6, c = 2; pn(a % b == c); }
pn(7 % 8 != -8);
{ int a = 7, b = 8, c = -8; pn(a % b != c); }
pn(9 % 9 < 3);
{ int a = 9, b = 9, c = 3; pn(a % b < c); }
pn(5 % -8 > 100);
{ int a = 5, b = -8, c = 100; pn(a % b > c); }
pn(8 % -8 <= 0);
{ int a = 8, b = -8, c = 0; pn(a % b <= c); }
pn(-1 % -2 >= 5);
{ int a = -1, b = -2, c = 5; pn(a % b >= c); }
pn(100 % 5 << 6);
{ int a = 100, b = 5, c = 6; pn(a % b << c); }
pn(-8 % 0 >> 2);
{ int a = -8, b = 0, c = 2; pn(a % b >> c); }
pn(-1 % 0 + -1);
{ int a = -1, b = 0, c = -1; pn(a % b + c); }
pn(-3 % 3 - 9);
{ int a = -3, b = 3, c = 9; pn(a % b - c); }
pn(5 % 2 * 4);
{ int a = 5, b = 2, c = 4; pn(a % b * c); }
pn(-8 % 5 / 100);
{ int a = -8, b = 5, c = 100; pn(a % b / c); }
pn(5 % 4 % 2);
{ int a = 5, b = 4, c = 2; pn(a % b % c); }
return 0;
}
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