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path: root/tests/conformance/3-expressions/prec_left_shr.zc
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// expect: 1/1/1/1/-4/-4/-6/-6/0/0/0/0/1/1/1/1/1/1/1/1/0/0/-128/-128/0/0/0/0/-1/-1/0/0/4/4/7/7/
// first operator >> followed by each other binary operator; operands chosen so that the two groupings differ
include rt;
void pn(int x) { rt.put_n(x); rt.put_c(10); }
fn main() {
	pn(9 >> 5 || 9);
	{ int a = 9, b = 5, c = 9; pn(a >> b || c); }
	pn(100 >> 6 && -1);
	{ int a = 100, b = 6, c = -1; pn(a >> b && c); }
	pn(4 >> 0 | -8);
	{ int a = 4, b = 0, c = -8; pn(a >> b | c); }
	pn(-3 >> 1 ^ 4);
	{ int a = -3, b = 1, c = 4; pn(a >> b ^ c); }
	pn(8 >> 3 & 0);
	{ int a = 8, b = 3, c = 0; pn(a >> b & c); }
	pn(5 >> 2 == 9);
	{ int a = 5, b = 2, c = 9; pn(a >> b == c); }
	pn(5 >> 7 != 1);
	{ int a = 5, b = 7, c = 1; pn(a >> b != c); }
	pn(-3 >> 0 < -2);
	{ int a = -3, b = 0, c = -2; pn(a >> b < c); }
	pn(100 >> 6 > -2);
	{ int a = 100, b = 6, c = -2; pn(a >> b > c); }
	pn(-8 >> 0 <= -3);
	{ int a = -8, b = 0, c = -3; pn(a >> b <= c); }
	pn(8 >> 7 >= 100);
	{ int a = 8, b = 7, c = 100; pn(a >> b >= c); }
	pn(-3 >> 3 << 7);
	{ int a = -3, b = 3, c = 7; pn(a >> b << c); }
	pn(6 >> 6 >> 5);
	{ int a = 6, b = 6, c = 5; pn(a >> b >> c); }
	pn(0 >> 2 + 8);
	{ int a = 0, b = 2, c = 8; pn(a >> b + c); }
	pn(-2 >> 0 - 4);
	{ int a = -2, b = 0, c = 4; pn(a >> b - c); }
	pn(9 >> 3 * 8);
	{ int a = 9, b = 3, c = 8; pn(a >> b * c); }
	pn(4 >> 0 / 4);
	{ int a = 4, b = 0, c = 4; pn(a >> b / c); }
	pn(7 >> 7 % 1);
	{ int a = 7, b = 7, c = 1; pn(a >> b % c); }
	return 0;
}